在ASP.NET MVC中处理分页,可以使用以下步骤:
public class PaginatedList<T> : List<T>
{
public int PageIndex { get; private set; }
public int TotalPages { get; private set; }
public int PageSize { get; private set; }
public int TotalCount { get; private set; }
public PaginatedList(IEnumerable<T> items, int count, int pageIndex, int pageSize)
{
TotalCount = count;
PageSize = pageSize;
PageIndex = pageIndex;
TotalPages = (int)Math.Ceiling(count / (double)pageSize);
AddRange(items);
}
public bool HasPreviousPage
{
get
{
return (PageIndex > 1);
}
}
public bool HasNextPage
{
get
{
return (PageIndex< TotalPages);
}
}
public static PaginatedList<T> Create(IQueryable<T> source, int pageIndex, int pageSize)
{
var count = source.Count();
var items = source.Skip((pageIndex - 1) * pageSize).Take(pageSize).ToList();
return new PaginatedList<T>(items, count, pageIndex, pageSize);
}
}
public ActionResult Index(int? page)
{
int pageSize = 10;
int pageNumber = (page ?? 1);
var items = db.Items.OrderBy(i => i.Id);
var model = PaginatedList<Item>.Create(items, pageNumber, pageSize);
return View(model);
}
@model PaginatedList<Item><table>
<tr>
<th>Id</th>
<th>Name</th>
</tr>
@foreach (var item in Model)
{
<tr>
<td>@item.Id</td>
<td>@item.Name</td>
</tr>
}
</table>
<div>
@if (Model.HasPreviousPage)
{
<a href="@Url.Action("Index", new { page = Model.PageIndex - 1 })">Previous</a>
}
@if (Model.HasNextPage)
{
<a href="@Url.Action("Index", new { page = Model.PageIndex + 1 })">Next</a>
}
</div>
这样,在ASP.NET MVC中就可以实现分页功能了。
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