如何在Python中使用try和except时仍显示错误消息

import traceback

def divide(x, y):
    try:
        result = x / y
    except ZeroDivisionError as e:
        print("捕获到异常:", e)
        traceback.print_exc()  # 打印详细的错误信息
    else:
        print("结果是:", result)

# 测试函数
divide(10, 0)

捕获到异常: division by zero
Traceback (most recent call last):
  File "<stdin>", line 4, in divide
    result = x / y
ZeroDivisionError: division by zero