如何在Javascript中进行"软"if条件检查

const condition = true;
const result = condition ? "条件为真" : "条件为假";

const condition = true;
const result = condition && "条件为真" || "条件为假";

const condition = true;
const result = (() => {
  switch (true) {
    case condition:
      return "条件为真";
    default:
      return "条件为假";
  }
})();

const condition = true;
let result;

if (condition) {
  result = "条件为真";
} else {
  result = "条件为假";
}