如何在GAE cron作业失败时获得通知？

from google.appengine.api import mail

def cron_job_handler(request):
    try:
        # 执行cron作业的代码
        pass
    except Exception as e:
        # 发送通知
        mail.send_mail(sender="admin@example.com",
                       to="developer@example.com",
                       subject="GAE Cron作业失败通知",
                       body="作业执行失败：%s" % str(e))

import logging

def cron_job_handler(request):
    try:
        # 执行cron作业的代码
        pass
    except Exception as e:
        # 记录错误信息到日志
        logging.error("GAE Cron作业执行失败：%s" % str(e))