如何在AJAX中传递Django url？

$.ajax({
  url: '/your-django-url/',  // 替换为你的Django URL
  method: 'POST',  // 根据实际需求选择请求方法
  data: {
    param1: 'value1',
    param2: 'value2'
  },
  success: function(response) {
    // 处理成功响应
  },
  error: function(xhr, status, error) {
    // 处理错误响应
  }
});

from django.urls import path
from . import views

urlpatterns = [
    path('your-django-url/', views.your_view_function, name='your-view'),
]

from django.http import JsonResponse

def your_view_function(request):
    param1 = request.POST.get('param1')
    param2 = request.POST.get('param2')
    
    # 处理参数并返回响应
    response_data = {
        'result': 'success',
        'message': 'AJAX request received',
        'param1': param1,
        'param2': param2
    }
    return JsonResponse(response_data)