如何在输出文件中删除标题名称中的空格

import re

# 读取输入文件
with open('input.txt', 'r') as file:
    content = file.read()

# 解析标题
title_start = content.index('Title:') + len('Title:')
title_end = content.index('\n', title_start)
title = content[title_start:title_end]

# 处理标题名称中的空格
processed_title = re.sub(r'\s', '', title)

# 更新输出文件
with open('output.txt', 'w') as file:
    file.write(content.replace(title, processed_title))

const fs = require('fs');

// 读取输入文件
const content = fs.readFileSync('input.txt', 'utf8');

// 解析标题
const titleStart = content.indexOf('Title:') + 'Title:'.length;
const titleEnd = content.indexOf('\n', titleStart);
const title = content.substring(titleStart, titleEnd);

// 处理标题名称中的空格
const processedTitle = title.replace(/\s/g, '');

// 更新输出文件
fs.writeFileSync('output.txt', content.replace(title, processedTitle));