如何在用ContextMenuItemSelected长点击时从ExpandableListView中删除一个项目？

registerForContextMenu(expandableListView);

@Override
public void onCreateContextMenu(ContextMenu menu, View v, ContextMenu.ContextMenuInfo menuInfo) {
    super.onCreateContextMenu(menu, v, menuInfo);
    MenuInflater inflater = getMenuInflater();
    inflater.inflate(R.menu.context_menu, menu); // R.menu.context_menu为自定义的菜单布局文件
}

@Override
public boolean onContextItemSelected(MenuItem item) {
    ExpandableListView.ExpandableListContextMenuInfo info = (ExpandableListView.ExpandableListContextMenuInfo) item.getMenuInfo();
    int groupPos = ExpandableListView.getPackedPositionGroup(info.packedPosition);
    int childPos = ExpandableListView.getPackedPositionChild(info.packedPosition);
    
    switch (item.getItemId()) {
        case R.id.delete_item:
            // 在这里执行删除操作
            // 根据groupPos和childPos获取要删除的项目，并从数据源中移除
            // 例如：dataList.get(groupPos).remove(childPos);
            // 更新ExpandableListView的显示
            // 例如：adapter.notifyDataSetChanged();
            return true;
        default:
            return super.onContextItemSelected(item);
    }
}

<menu xmlns:android="http://schemas.android.com/apk/res/android">
    <item
        android:id="@+id/delete_item"
        android:title="删除" />
</menu>