如何在没有属性名的情况下反序列化Json .net核心newtonsoft

using Newtonsoft.Json.Linq;
using System;
using System.Collections.Generic;

public class Program
{
    public static void Main()
    {
        string json = @"[
            {
                ""Name"": ""John"",
                ""Age"": 30,
                ""City"": ""New York""
            },
            {
                ""Name"": ""Jane"",
                ""Age"": 28,
                ""City"": ""Los Angeles""
            }
        ]";

        // 反序列化为JArray
        JArray jsonArray = JArray.Parse(json);

        // 遍历JArray并访问每个JObject的属性
        foreach (JObject jsonObject in jsonArray)
        {
            string name = jsonObject["Name"]?.ToString();
            int age = jsonObject["Age"]?.ToObject<int>() ?? 0;
            string city = jsonObject["City"]?.ToString();

            Console.WriteLine($"Name: {name}, Age: {age}, City: {city}");
        }
    }
}

using Newtonsoft.Json;
using System;

public class Program
{
    public static void Main()
    {
        string json = @"{
            ""data"": [
                {
                    ""value"": 1
                },
                {
                    ""value"": 2
                }
            ]
        }";

        // 反序列化为dynamic类型
        dynamic result = JsonConvert.DeserializeObject<dynamic>(json);

        // 访问dynamic对象的属性
        foreach (var item in result.data)
        {
            Console.WriteLine(item.value);
        }
    }
}