如何在构造JSON响应时删除空属性

// 假设要构造的JSON对象
const data = {
  name: "John",
  age: null,
  email: "",
  address: {
    street: "123 Main St",
    city: "",
    country: undefined
  }
};

// 递归函数，用于删除空属性
function removeEmptyProperties(obj) {
  for (let prop in obj) {
    if (obj[prop] === null || obj[prop] === "" || obj[prop] === undefined) {
      delete obj[prop];
    } else if (typeof obj[prop] === "object") {
      removeEmptyProperties(obj[prop]);
    }
  }
}

// 删除空属性
removeEmptyProperties(data);

// 输出最终的JSON响应
console.log(JSON.stringify(data));