如何在不将id从angular应用程序传递到带有ngrx/entity的firestore的情况下创建项目？

// 项目模型
export interface Project {
  id?: string;
  name: string;
  description: string;
  createdDate: Date;
}

// 项目服务
import { Injectable } from '@angular/core';
import { AngularFirestore, AngularFirestoreCollection } from '@angular/fire/firestore';
import { Observable } from 'rxjs';
import { map } from 'rxjs/operators';

@Injectable({
  providedIn: 'root'
})
export class ProjectService {
  private projectsCollection: AngularFirestoreCollection<Project>;

  constructor(private firestore: AngularFirestore) {
    this.projectsCollection = this.firestore.collection<Project>('projects');
  }

  createProject(project: Project): Promise<void> {
    const id = this.firestore.createId();
    const newProject: Project = { ...project, id };

    return this.projectsCollection.doc(id).set(newProject);
  }

  getProjects(): Observable<Project[]> {
    return this.projectsCollection.snapshotChanges().pipe(
      map(actions => {
        return actions.map(a => {
          const data = a.payload.doc.data() as Project;
          const id = a.payload.doc.id;
          return { id, ...data };
        });
      })
    );
  }
}

// 组件
import { Component } from '@angular/core';
import { ProjectService } from './project.service';

@Component({
  selector: 'app-create-project',
  template: `
    <form (submit)="createProject()">
      <input type="text" [(ngModel)]="name" placeholder="项目名称" required>
      <input type="text" [(ngModel)]="description" placeholder="项目描述" required>
      <button type="submit">创建项目</button>
    </form>
  `
})
export class CreateProjectComponent {
  name: string;
  description: string;

  constructor(private projectService: ProjectService) {}

  createProject(): void {
    const project: Project = {
      name: this.name,
      description: this.description,
      createdDate: new Date()
    };

    this.projectService.createProject(project)
      .then(() => {
        console.log('项目创建成功');
        // 可以在此处进行重定向或其他操作
      })
      .catch(error => {
        console.error('项目创建失败', error);
      });
  }
}