如何在不出现内存问题的情况下在python中读取大型XML文件

import xml.etree.ElementTree as ET

def process_element(element):
    # 处理每个元素的逻辑
    pass

def parse_large_xml(file_path):
    for event, element in ET.iterparse(file_path):
        if element.tag == 'your_tag':
            process_element(element)
            element.clear()  # 释放元素占用的内存

import xml.sax

class MyHandler(xml.sax.ContentHandler):
    def startElement(self, name, attrs):
        # 处理每个元素的逻辑
        pass

def parse_large_xml(file_path):
    handler = MyHandler()
    parser = xml.sax.make_parser()
    parser.setContentHandler(handler)
    parser.parse(open(file_path, "rb"))

from lxml import etree

def process_element(element):
    # 处理每个元素的逻辑
    pass

def parse_large_xml(file_path):
    context = etree.iterparse(file_path, events=('end',))
    for event, element in context:
        if element.tag == 'your_tag':
            process_element(element)
        element.clear()  # 释放元素占用的内存
        while element.getprevious() is not None:
            del element.getparent()[0]