如何合并任意数量的字典和连接具有公共键的值

def merge_dicts(*dicts, join_on=None, join_func=lambda x, y: x + y):
    """
    合并任意数量的字典，并连接具有公共键的值。

    :param dicts: 任意数量的字典
    :param join_on: 连接键的名称，默认为None，表示不连接值
    :param join_func: 连接值的函数，默认为简单的字符串连接
    :return: 合并后的字典
    """
    merged_dict = {}
    for d in dicts:
        for key, value in d.items():
            if key in merged_dict:
                if join_on is not None:
                    if isinstance(merged_dict[key], list):
                        merged_dict[key].append(value)
                    else:
                        merged_dict[key] = [merged_dict[key], value]
                    merged_dict[key] = join_func(*merged_dict[key])
                else:
                    merged_dict[key] = value
            else:
                merged_dict[key] = value
    return merged_dict

# 示例数据
dict1 = {'a': 1, 'b': 2}
dict2 = {'a': 3, 'c': 4}
dict3 = {'b': 5, 'd': 6}

# 合并字典并连接具有公共键的值
result = merge_dicts(dict1, dict2, dict3, join_on='a', join_func=lambda x, y: x + y)
print(result)