如何停止所有等待sync.Cond的goroutine？

var cond = sync.NewCond(&sync.Mutex{})

cond.L.Lock()
cond.Wait()
cond.L.Unlock()

cond.Broadcast()

package main

import (
    "fmt"
    "sync"
    "time"
)

var cond = sync.NewCond(&sync.Mutex{})
var wg sync.WaitGroup

func main() {
    for i := 0; i < 5; i++ {
        wg.Add(1)
        go worker(i)
    }

    time.Sleep(time.Second * 2) // 为了确保所有goroutine都开始等待

    fmt.Println("Stopping all goroutines...")
    cond.Broadcast() // 停止所有等待的goroutine
    wg.Wait()        // 等待所有goroutine完成
    fmt.Println("All goroutines stopped.")
}

func worker(id int) {
    defer wg.Done()

    fmt.Printf("Worker %d is waiting...\n", id)

    cond.L.Lock()
    cond.Wait()
    cond.L.Unlock()

    fmt.Printf("Worker %d resumed.\n", id)
}