如何使用python识别字符串中有序的子字符串？

def find_ordered_substrings(string, substring):
    result = []
    start = 0
    while True:
        index = string.find(substring, start)
        if index == -1:
            break
        result.append((index, index + len(substring) - 1))
        start = index + len(substring)
    return result

# 示例用法
string = "ababcabcabc"
substring = "abc"
result = find_ordered_substrings(string, substring)
print(result)