如何使用log4j2避免重复记录唯一ID

<Configuration>
  <Appenders>
    <Console name="Console" target="SYSTEM_OUT">
      <PatternLayout pattern="%d{HH:mm:ss.SSS} [%t] %-5level %logger{36} - %msg%n"/>
      <Filters>
        <DuplicateIdFilter/>
      </Filters>
    </Console>
  </Appenders>
  <Loggers>
    <Root level="info">
      <AppenderRef ref="Console"/>
    </Root>
  </Loggers>
</Configuration>

import org.apache.logging.log4j.core.Filter;
import org.apache.logging.log4j.core.LogEvent;
import import org.apache.logging.log4j.core.Logger;
import org.apache.logging.log4j.core.config.plugins.Plugin;
import org.apache.logging.log4j.core.filter.AbstractFilter;

@Plugin(name = "DuplicateIdFilter", category = "Core", elementType = "filter", printObject = true)
public class DuplicateIdFilter extends AbstractFilter {

    private String lastId;

    @Override
    public Result shouldLog(LogEvent event) {
        String currentId = event.getContextData().getValue("uniqueId").toString();
        if (currentId.equals(lastId)) {
            return Result.DENY;
        } else {
            lastId = currentId;
            return Result.NEUTRAL;
        }
    }
}

import org.apache.logging.log4j.LogManager;
import org.apache.logging.log4j.Logger;
import org.apache.logging.log4j.ThreadContext;

public class MyClass {
    private static final Logger logger = LogManager.getLogger(MyClass.class);

    public void doSomething() {
        String uniqueId = generateUniqueId();
        ThreadContext.put("uniqueId", uniqueId);
        logger.info("This is a log message with unique ID: {}", uniqueId);
        ThreadContext.remove("uniqueId");
    }

    private String generateUniqueId() {
        // 生成唯一ID的逻辑
        return "1234567890";
    }
}