如何使用ToDeleteItems数组删除多个嵌套对象

function deleteNestedObjects(nestedObject, toDeleteItems) {
  for (let i = 0; i < toDeleteItems.length; i++) {
    const item = toDeleteItems[i];
    deleteObject(nestedObject, item);
  }
}

function deleteObject(obj, item) {
  for (let key in obj) {
    if (obj.hasOwnProperty(key)) {
      if (typeof obj[key] === 'object') {
        deleteObject(obj[key], item); // 递归调用以处理嵌套对象
      } else if (obj[key] === item) {
        delete obj[key]; // 删除匹配的对象
      }
    }
  }
}

// 示例用法
const nestedObject = {
  foo: {
    bar: {
      baz: 'value1',
      qux: 'value2'
    },
    baz: 'value3'
  },
  bar: {
    baz: 'value4'
  }
};

const toDeleteItems = ['value1', 'value3'];

deleteNestedObjects(nestedObject, toDeleteItems);

console.log(nestedObject);