如何使用PHP和mysqli连接两个表并得到以下结果？

$servername = "localhost";
$username = "your_username";
$password = "your_password";
$dbname = "your_database";

$conn = mysqli_connect($servername, $username, $password, $dbname);

if (!$conn) {
    die("连接失败: " . mysqli_connect_error());
}

$sql = "SELECT table1.column1, table2.column2
        FROM table1
        JOIN table2 ON table1.id = table2.id";

$result = mysqli_query($conn, $sql);

if (mysqli_num_rows($result) > 0) {
    while ($row = mysqli_fetch_assoc($result)) {
        echo "column1: " . $row["column1"]. " - column2: " . $row["column2"]. "<br>";
    }
} else {
    echo "0 结果";
}

mysqli_close($conn);