如何使用JAXB为同一个类实现两种不同的输出？

import javax.xml.bind.JAXBContext;
import javax.xml.bind.JAXBException;
import javax.xml.bind.Marshaller;
import java.io.File;
import java.io.StringWriter;

public class JAXBExample {
    public static void main(String[] args) {
        try {
            // 创建JAXBContext对象
            JAXBContext jaxbContext = JAXBContext.newInstance(YourClass.class);

            // 创建第一个Marshaller对象，用于生成文件输出
            Marshaller fileMarshaller = jaxbContext.createMarshaller();
            fileMarshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);

            // 创建第二个Marshaller对象，用于生成字符串输出
            Marshaller stringMarshaller = jaxbContext.createMarshaller();
            stringMarshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);

            // 创建Java对象
            YourClass obj = new YourClass();

            // 第一个输出：生成XML文件
            File file = new File("output.xml");
            fileMarshaller.marshal(obj, file);

            // 第二个输出：生成XML字符串
            StringWriter stringWriter = new StringWriter();
            stringMarshaller.marshal(obj, stringWriter);
            String xmlString = stringWriter.toString();

            System.out.println("XML文件输出成功：" + file.getAbsolutePath());
            System.out.println("XML字符串输出成功：" + xmlString);
        } catch (JAXBException e) {
            e.printStackTrace();
        }
    }
}