如何从Python中的object函数返回嵌套的对象路径？

def get_nested_path(obj, target, path=None):
    if path is None:
        path = []

    if obj == target:
        return path

    if isinstance(obj, dict):
        for key, value in obj.items():
            new_path = path + [key]
            result = get_nested_path(value, target, new_path)
            if result is not None:
                return result
    elif hasattr(obj, '__dict__'):  # 对于自定义对象
        for key, value in obj.__dict__.items():
            new_path = path + [key]
            result = get_nested_path(value, target, new_path)
            if result is not None:
                return result
    elif isinstance(obj, (list, tuple)):
        for index, value in enumerate(obj):
            new_path = path + [index]
            result = get_nested_path(value, target, new_path)
            if result is not None:
                return result

    return None

# 示例使用
nested_obj = {
    'a': {
        'b': [
            {'c': 1},
            {'d': 2}
        ]
    }
}

target_value = 2
path = get_nested_path(nested_obj, target_value)
print(f"The path to the target value {target_value} is: {' -> '.join(map(str, path))}")