如何从JQuery调用CakepPHP 3操作

$.ajax({
  url: '/controller/action',
  type: 'POST',
  data: {param1: value1, param2: value2},
  success: function(response) {
    // 处理成功响应
  },
  error: function(xhr, status, error) {
    // 处理错误响应
  }
});

namespace App\Controller;

use Cake\Controller\Controller;
use Cake\Network\Exception\NotFoundException;

class MyController extends Controller
{
  public function action()
  {
    if ($this->request->is('ajax')) {
      $param1 = $this->request->getData('param1');
      $param2 = $this->request->getData('param2');
      
      // 在这里执行你的操作，例如查询数据库、处理业务逻辑等
      
      $response = ['result' => 'success'];
      $this->set(compact('response'));
      $this->viewBuilder()->setLayout('ajax');
    } else {
      throw new NotFoundException();
    }
  }
}

success: function(response) {
  // 处理成功响应
  console.log(response.result);
}