如何从列表列表中提取href

from bs4 import BeautifulSoup

# 假设列表的HTML代码存储在变量html中
html = """
<ul>
  <li><a href="https://www.example.com/page1">Link 1</a></li>
  <li><a href="https://www.example.com/page2">Link 2</a></li>
  <li><a href="https://www.example.com/page3">Link 3</a></li>
</ul>
"""

# 使用BeautifulSoup解析HTML
soup = BeautifulSoup(html, 'html.parser')

# 找到所有包含href属性的<a>标签
links = soup.find_all('a', href=True)

# 遍历每个链接并提取href属性的值
for link in links:
    href = link['href']
    print(href)

https://www.example.com/page1
https://www.example.com/page2
https://www.example.com/page3