如何为成员类型为string的结构变量分配内存

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

struct MyStruct {
    char* myString;
};

int main() {
    struct MyStruct* myVar = malloc(sizeof(struct MyStruct));
    myVar->myString = malloc(sizeof(char) * (strlen("Hello, World!") + 1));  // 分配足够的内存存储字符串及结尾的'\0'
    strcpy(myVar->myString, "Hello, World!");
    
    printf("%s\n", myVar->myString);
    
    free(myVar->myString);  // 释放字符串内存
    free(myVar);  // 释放结构变量内存
    
    return 0;
}

#include <iostream>
#include <string>

struct MyStruct {
    std::string myString;
};

int main() {
    MyStruct* myVar = new MyStruct;
    myVar->myString = "Hello, World!";
    
    std::cout << myVar->myString << std::endl;
    
    delete myVar;
    
    return 0;
}