多个ids容差范围内的最接近值

def find_closest_id(ids, target):
    min_diff = float('inf')  # 初始化最小差值为正无穷大
    closest_id = None

    for id in ids:
        diff = abs(id - target)  # 计算差值的绝对值
        if diff < min_diff:
            min_diff = diff
            closest_id = id

    return closest_id

# 示例用法
ids = [1, 5, 10, 15, 20]
target = 12
closest_id = find_closest_id(ids, target)
print("与目标值最接近的id是:", closest_id)