基于用户输入移动嵌套列表中的元素索引

nested_list = [1, [2, [3, 4], 5], [6, 7]]

element = nested_list[1] # 获取索引为1的元素，即[2, [3, 4], 5]
result = element[0] # 获取索引为0的元素，即2

def get_nested_element(nested_list, index_list):
    element = nested_list
    try:
        for index in index_list:
            element = element[index]
        return element
    except (IndexError, TypeError):
        return None

nested_list = [1, [2, [3, 4], 5], [6, 7]]
index_list = [1, 0]
result = get_nested_element(nested_list, index_list)
print(result) # 输出2