在python中对文件的数据列表进行排序，以计算学生的成绩

Alice 85
Bob 92
Charlie 78
David 88

# 读取文件数据
with open('students.txt', 'r') as file:
    students = [line.strip().split() for line in file]

# 将数据转换为字典列表
students = [{'name': name, 'score': int(score)} for name, score in students]

# 按成绩升序排序
sorted_students = sorted(students, key=lambda x: x['score'])

# 打印排序后的结果
for student in sorted_students:
    print(f"{student['name']}: {student['score']}")

try:
    with open('students.txt', 'r') as file:
        students = [line.strip().split() for line in file]
except FileNotFoundError:
    print("文件不存在，请检查文件路径。")

students = []
with open('students.txt', 'r') as file:
    for line in file:
        try:
            name, score = line.strip().split()
            students.append({'name': name, 'score': int(score)})
        except ValueError:
            print(f"数据格式错误: {line.strip()}")