在python中使用regex从字符串中提取不同格式的日期

import re

pattern = r"\d{4}-\d{2}-\d{2}"

pattern = r"\d{2}/\d{2}/\d{4}"

pattern = r"\d{2}-\d{2}-\d{4}"

string = "Today is 2022-01-01, tomorrow is 01/02/2022, and yesterday was 01-01-2022."
dates = re.findall(pattern, string)

for date in dates:
    print(date)

import re

string = "Today is 2022-01-01, tomorrow is 01/02/2022, and yesterday was 01-01-2022."

# YYYY-MM-DD
pattern = r"\d{4}-\d{2}-\d{2}"
dates = re.findall(pattern, string)
print("YYYY-MM-DD:")
for date in dates:
    print(date)

# MM/DD/YYYY
pattern = r"\d{2}/\d{2}/\d{4}"
dates = re.findall(pattern, string)
print("MM/DD/YYYY:")
for date in dates:
    print(date)

# DD-MM-YYYY
pattern = r"\d{2}-\d{2}-\d{4}"
dates = re.findall(pattern, string)
print("DD-MM-YYYY:")
for date in dates:
    print(date)