在javascript中组合多个类似的函数

const compose = (...fns) => (arg) => fns.reduceRight((acc, fn) => fn(acc), arg);

const add = (x) => x + 1;
const multiply = (x) => x * 2;
const subtract = (x) => x - 3;

const combinedFunction = compose(add, multiply, subtract);
console.log(combinedFunction(5)); // 输出：7

const numbers = [1, 2, 3, 4, 5];

const addOne = (x) => x + 1;
const multiplyByTwo = (x) => x * 2;
const subtractThree = (x) => x - 3;

const combinedFunction = (arr, fn) => arr.map(fn);

console.log(combinedFunction(numbers, addOne)); // 输出：[2, 3, 4, 5, 6]
console.log(combinedFunction(numbers, multiplyByTwo)); // 输出：[2, 4, 6, 8, 10]
console.log(combinedFunction(numbers, subtractThree)); // 输出：[-2, -1, 0, 1, 2]

const curry = (fn) => {
  const arity = fn.length;

  return function $curry(...args) {
    if (args.length < arity) {
      return $curry.bind(null, ...args);
    }

    return fn.call(null, ...args);
  };
};

const add = (x, y) => x + y;
const multiply = (x, y) => x * y;
const subtract = (x, y) => x - y;

const curriedAdd = curry(add);
const curriedMultiply = curry(multiply);
const curriedSubtract = curry(subtract);

console.log(curriedAdd(1)(2)); // 输出：3
console.log(curriedMultiply(2)(3)); // 输出：6
console.log(curriedSubtract(5)(3)); // 输出：2