在Java中重新排列ArrayList的最佳方法

import java.util.ArrayList;
import java.util.Collections;

public class Main {
    public static void main(String[] args) {
        ArrayList<Integer> arrayList = new ArrayList<>();
        arrayList.add(10);
        arrayList.add(5);
        arrayList.add(8);
        arrayList.add(3);

        Collections.sort(arrayList);

        System.out.println("Sorted ArrayList: " + arrayList);
    }
}

Sorted ArrayList: [3, 5, 8, 10]

import java.util.ArrayList;
import java.util.Collections;
import java.util.Comparator;

public class Main {
    public static void main(String[] args) {
        ArrayList<Person> arrayList = new ArrayList<>();
        arrayList.add(new Person("Tom", 30));
        arrayList.add(new Person("Jerry", 20));
        arrayList.add(new Person("Alice", 25));

        Collections.sort(arrayList, new Comparator<Person>() {
            @Override
            public int compare(Person p1, Person p2) {
                return p1.getAge() - p2.getAge();
            }
        });

        System.out.println("Sorted ArrayList: " + arrayList);
    }
}

class Person {
    private String name;
    private int age;

    public Person(String name, int age) {
        this.name = name;
        this.age = age;
    }

    public String getName() {
        return name;
    }

    public int getAge() {
        return age;
    }

    @Override
    public String toString() {
        return "Person{" +
                "name='" + name + '\'' +
                ", age=" + age +
                '}';
    }
}

Sorted ArrayList: [Person{name='Jerry', age=20}, Person{name='Alice', age=25}, Person{name='Tom', age=30}]