在Java中,如何将XML解析为String而不是文件？

import javax.xml.bind.annotation.XmlRootElement;

@XmlRootElement
public class Person {
    private String name;
    private int age;

    public Person() {}

    public Person(String name, int age) {
        this.name = name;
        this.age = age;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public int getAge() {
        return age;
    }

    public void setAge(int age) {
        this.age = age;
    }
}

import javax.xml.bind.JAXBContext;
import javax.xml.bind.JAXBException;
import javax.xml.bind.Marshaller;
import java.io.StringWriter;

public class XmlStringExample {
    public static void main(String[] args) {
        Person person = new Person("John Doe", 30);

        try {
            JAXBContext jaxbContext = JAXBContext.newInstance(Person.class);
            Marshaller marshaller = jaxbContext.createMarshaller();
            marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);

            StringWriter stringWriter = new StringWriter();
            marshaller.marshal(person, stringWriter);

            String xmlString = stringWriter.toString();
            System.out.println(xmlString);
        } catch (JAXBException e) {
            e.printStackTrace();
        }
    }
}

<?xml version="1.0" encoding="UTF-8" standalone="yes"?><person>
    <age>30</age>
    <name>John Doe</name>
</person>