在Django Rest框架中生成OpenAPI模式:更新ViewSet中的URL关键字

from rest_framework.viewsets import ViewSet
from rest_framework.decorators import action
from rest_framework.response import Response
from drf_yasg.utils import swagger_auto_schema

class MyViewSet(ViewSet):
    @swagger_auto_schema(tags=['My API'])
    @action(detail=False, methods=['get'], url_path='openapi')
    def openapi_view(self, request):
        """
        生成OpenAPI模式
        """
        # 在此处编写生成OpenAPI模式的逻辑
        return Response({'message': 'OpenAPI模式生成成功'})

from django.urls import path, include
from .views import MyViewSet

urlpatterns = [
    path('api/', include(MyViewSet.as_view({'get': 'list', 'post': 'create', ...}).urls)),
]