在C#中快速将350M数字加载到double []数组中

byte[] byteArray = new byte[350 * 1024 * 1024];
double[] doubleArray = new double[350 * 1024 * 1024 / 8];
Buffer.BlockCopy(byteArray, 0, doubleArray, 0, byteArray.Length);

unsafe
{
    byte[] byteArray = new byte[350 * 1024 * 1024];
    double[] doubleArray = new double[350 * 1024 * 1024 / 8];
    fixed (byte* bytePtr = byteArray)
    {
        fixed (double* doublePtr = doubleArray)
        {
            for (int i = 0; i< doubleArray.Length; i++)
            {
                doublePtr[i] = *(double*)(bytePtr + i * 8);
            }
        }
    }
}

byte[] byteArray = new byte[350 * 1024 * 1024];
double[] doubleArray = new double[350 * 1024 * 1024 / 8];
Parallel.For(0, doubleArray.Length, i =>
{
    doubleArray[i] = BitConverter.ToDouble(byteArray, i * 8);
});