在字符串中查找连续的字母表

def find_consecutive_alphabets(string):
    consecutive_alphabets = []
    start = 0
    length = 0

    for i in range(len(string)):
        if string[i].isalpha():
            if length == 0:
                start = i
                length = 1
            elif ord(string[i]) == ord(string[i-1]) + 1:
                length += 1
            else:
                if length > 1:
                    consecutive_alphabets.append((start, length))
                start = i
                length = 1

    if length > 1:
        consecutive_alphabets.append((start, length))

    return consecutive_alphabets

# 示例用法
string = "abcdehijklmnopqrstuvwxy"
result = find_consecutive_alphabets(string)
print(result)