在一个选项html form php mysql中选择两个值

<form action="process.php" method="post">
  <label for="option1">选项1：</label>
  <select name="option1" id="option1">
    <option value="value1">值1</option>
    <option value="value2">值2</option>
    <option value="value3">值3</option>
  </select>
  
  <label for="option2">选项2：</label>
  <select name="option2" id="option2">
    <option value="value4">值4</option>
    <option value="value5">值5</option>
    <option value="value6">值6</option>
  </select>
  
  <input type="submit" value="提交">
</form>

$option1 = $_POST['option1'];
$option2 = $_POST['option2'];

// 对获取到的值进行处理或存储到数据库中
// ...

// 连接到MySQL数据库
$servername = "localhost";
$username = "your_username";
$password = "your_password";
$dbname = "your_database";

$conn = new mysqli($servername, $username, $password, $dbname);

// 检查连接是否成功
if ($conn->connect_error) {
    die("连接失败: " . $conn->connect_error);
}

// 创建存储值的表（如果不存在）
$sql = "CREATE TABLE IF NOT EXISTS options (
    id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY,
    option1 VARCHAR(30) NOT NULL,
    option2 VARCHAR(30) NOT NULL
)";

if ($conn->query($sql) === TRUE) {
    echo "表创建成功";
} else {
    echo "表创建失败: " . $conn->error;
}

// 将选项值插入到表中
$sql = "INSERT INTO options (option1, option2) VALUES ('$option1', '$option2')";

if ($conn->query($sql) === TRUE) {
    echo "记录插入成功";
} else {
    echo "插入记录时出错: " . $conn->error;
}

// 关闭数据库连接
$conn->close();