同构字符串(简单的方法？)

def isIsomorphic(s: str, t: str) -> bool:
    if len(s) != len(t):
        return False
    
    s_to_t = {}  # 用于记录s中字符到t中字符的映射关系
    t_to_s = {}  # 用于记录t中字符到s中字符的映射关系
    
    for i in range(len(s)):
        if s[i] in s_to_t:
            if s_to_t[s[i]] != t[i]:
                return False
        else:
            s_to_t[s[i]] = t[i]
        
        if t[i] in t_to_s:
            if t_to_s[t[i]] != s[i]:
                return False
        else:
            t_to_s[t[i]] = s[i]
    
    return True