使用zip()、map()函数和itertools对列表中的列表元素求和

# 定义两个列表
list1 = [1, 2, 3]
list2 = [4, 5, 6]

# 使用zip()函数将两个列表打包成元组的列表
zipped = zip(list1, list2)

# 使用map()函数和一个lambda表达式来计算每对元素的和
summed = map(lambda pair: sum(pair), zipped)

# 将map对象转换为列表
result = list(summed)

print(result)  # 输出: [5, 7, 9]

list3 = [7, 8, 9]
zipped = zip(list1, list2, list3)
summed = map(lambda triplet: sum(triplet), zipped)
result = list(summed)
print(result)  # 输出: [12, 15, 18]

import itertools

nested_list = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
flattened = itertools.chain(*nested_list)
total_sum = sum(flattened)

print(total_sum)  # 输出: 45

import itertools

list1 = [1, 2, 3, 7]
list2 = [4, 5, 6]

zipped = itertools.zip_longest(list1, list2, fillvalue=0)
summed = map(lambda pair: sum(pair), zipped)
result = list(summed)

print(result)  # 输出: [5, 7, 9, 7]