使用3个PetersonLocks的数组来同步4个进程

# 初始化3个PetersonLocks的数组
locks = [PetersonLock() for _ in range(3)]

# 进程1
def process1():
    locks[0].flag[1] = True
    locks[0].turn = 1
    while locks[0].flag[0] and locks[0].turn == 1:
        pass
    # 进入临界区
    # 访问共享资源
    # 离开临界区
    locks[0].flag[1] = False

# 进程2
def process2():
    locks[1].flag[2] = True
    locks[1].turn = 2
    while locks[1].flag[1] and locks[1].turn == 2:
        pass
    # 进入临界区
    # 访问共享资源
    # 离开临界区
    locks[1].flag[2] = False

# 进程3
def process3():
    locks[2].flag[0] = True
    locks[2].turn = 0
    while locks[2].flag[2] and locks[2].turn == 0:
        pass
    # 进入临界区
    # 访问共享资源
    # 离开临界区
    locks[2].flag[0] = False

# 进程4
def process4():
    locks[0].flag[0] = True
    locks[0].turn = 0
    while locks[0].flag[1] and locks[0].turn == 0:
        pass
    # 进入临界区
    # 访问共享资源
    # 离开临界区
    locks[0].flag[0] = False

# 启动4个进程
process1()
process2()
process3()
process4()