使用不带缓冲变量的sprintf

int sprintf(char *str, const char *format, ...);

#include <stdio.h>

int main() {
    char buffer[256]; // 分配一个足够大的缓冲区
    int number = 123;
    const char *text = "Hello";

    // 使用sprintf将格式化的数据写入buffer
    int result = sprintf(buffer, "%s, the number is %d", text, number);

    if (result < 0) {
        // 处理错误情况
        printf("Error formatting string.\n");
    } else {
        printf("Formatted string: %s\n", buffer);
    }

    return 0;
}

int snprintf(char *str, size_t size, const char *format, ...);

#include <stdio.h>

int main() {
    char buffer[256];
    int number = 123;
    const char *text = "Hello";

    // 使用snprintf安全地写入buffer
    int result = snprintf(buffer, sizeof(buffer), "%s, the number is %d", text, number);

    if (result >= sizeof(buffer)) {
        // 数据被截断
        printf("Warning: formatted string was truncated.\n");
    } else if (result < 0) {
        // 处理错误情况
        printf("Error formatting string.\n");
    } else {
        printf("Formatted string: %s\n", buffer);
    }

    return 0;
}