以最有效的方式提取字符串中包含在复杂括号中的字符

def extract_bracket_content(s):
    stack = []
    result = []
    current = []
    
    for char in s:
        if char in "({[":
            stack.append(char)
            current.append(char)
        elif char in ")}]":
            if stack:
                stack.pop()
                current.append(char)
                if not stack:
                    result.append(''.join(current))
                    current = []
        elif stack:
            current.append(char)
    
    return result

# 示例字符串
s = "这是一个示例字符串 (包含[嵌套]的{复杂}括号) 和其他文本。"
print(extract_bracket_content(s))