为什么我在使用java.util.zip.ZipFile打开一个空的ZIP文件时遇到异常？

import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.util.zip.ZipEntry;
import java.util.zip.ZipInputStream;
import java.util.zip.ZipOutputStream;

public class EmptyZipFileExample {

    public static void main(String[] args) throws IOException {
        createEmptyZipFile("empty.zip");
        readEmptyZipFile("empty.zip");
    }

    public static void createEmptyZipFile(String fileName) throws IOException {
        try (ZipOutputStream zos = new ZipOutputStream(new FileOutputStream(fileName))) {
            // 此处不需要添加任何内容，因为我们要创建一个空的 ZIP 文件
        }
    }

    public static void readEmptyZipFile(String fileName) throws IOException {
        try (ZipInputStream zis = new ZipInputStream(new FileInputStream(fileName))) {
            ZipEntry zipEntry;
            while ((zipEntry = zis.getNextEntry()) != null) {
                System.out.println("Entry: " + zipEntry.getName());
                // 此处不需要执行任何操作，因为 ZIP 文件中没有内容可供读取
            }
        }
    }
}