一种更快的条件搜索嵌套字典的方法

def search_nested_dict(nested_dict, condition):
    result = []
    
    def dfs(dictionary, path):
        for key, value in dictionary.items():
            if isinstance(value, dict):
                dfs(value, path + [key])
            else:
                if condition(key, value):
                    result.append(path + [key])
    
    dfs(nested_dict, [])
    return result

nested_dict = {
    'a': {
        'b': {
            'c': 1,
            'd': 2
        },
        'e': {
            'f': 3,
            'g': 4
        }
    },
    'h': {
        'i': {
            'j': 5,
            'k': 6
        },
        'l': {
            'm': 7,
            'n': 8
        }
    }
}

def condition(key, value):
    return value > 3

result = search_nested_dict(nested_dict, condition)
print(result)  # 输出 [['h', 'l', 'm'], ['h', 'l', 'n']]