我生成了一个包含150个质量值的列表。我需要从这个列表中选择0.2-0.5,0.5-1.2等值,然后找到列表中这些部分的中位数和范围,但我尝试的每个函数都需要整数项和范围限制。是否有浮点数的等价物?我尝试过range()
和np.where
等。
发布于 2019-02-25 23:18:18
你可以试试这个:
from random import random
from statistics import median
masses = [ random()*10 for _ in range(150) ]
intervals = [ (0.2,0.5),(0.5,1.2) ]
for (low,high) in intervals:
inRange = [ mass for mass in masses if mass >= low and mass < high ]
print("(",low,",",high,") count=",len(inRange),"median=",median(inRange), "range=", min(inRange),"-",max(inRange))
https://stackoverflow.com/questions/54875952
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