来源是:
id, pid,name
1, 0, a
2, 1, b
3, 1, c我们预期的结果是:
id,pid,name,upnum,uplevel,downum,downlevel
1, 0, a, 0, 0, 2, 1
2, 1, b, 1, 1, 0, 0
3, 1, c, 1, 1, 0, 0在这里,name是人名,id表示每个人,pid表示家长id,例如a是b的上级。upnum表示他总共有多少上级,uplevel表示他有多少上级,downnum和downlevel几乎是这样的。
为了得到这个结果,我想我有两种方法
1.使用数据库,像oralce,我使用connect by和nocycle,每个人的所有东西都是ok.But,我必须再次运行"connect by“sql,它似乎很慢。而且我们必须在客户端安装一个oracle,有些客户端不喜欢它。如果我们使用h2或一些嵌入式数据库,我们可以在oracle中使用nocycle的功能吗?但我猜我们应该对id的索引进行too.Or。
2.使用java hashMap来存储id和pid的关系,但是当数据量变大时,可能会出现内存不足的exception.How来编写代码?
最好的方法是什么?或者有没有更好的方法?比如一些图形算法,或者是graph -db(数据库)?
发布于 2019-03-11 22:50:55
实际上并不需要数据库。一个简单的迭代和一个递归函数就可以完成所需的分析:
import java.util.ArrayList;
import java.util.List;
public class Graph {
private final List<Node> nodes;
private final Node root;
//Graph assumes unique id > 0, and only root with pid = 0
Graph(Node root){
this.root = root;
nodes = new ArrayList<>();
nodes.add(root);
};
void add(Node node){
nodes.add(node);
}
void analyze(){
//sort by pid so iteration goes from top level down
nodes.sort( (n1,n2) -> Integer.compare(n1.getPid(), n2.getPid()) );
for(Node node : nodes){
Node parent = getNode(node.getPid());
if (parent == null ) {
continue; //skip root
}
node.setUpLevel(parent.getUpLevel()+1); //add 1 to parent value
node.setUpNum(node.getUpNum() +1); //increment by 1
parent.setDowNum(parent.getDowNum() +1); //increment by 1
updateHigherLevels(node);
}
}
//recursively update higher levels
private void updateHigherLevels(Node node) {
Node parent = getNode(node.getPid());
if(parent == null) return;
parent.setDownLevel(node.getDownLevel() + 1);
updateHigherLevels(parent);
}
void print(){
//sort by id for nice printing
nodes.sort( (n1,n2) -> Integer.compare(n1.getId(), n2.getId()) );
String format = "\n%2s %3s %4s %5s %7s %7s %8s";
System.out.printf(format,"id","pid","name","upnum","uplevel", "downnum" , "downlevel");
for(Node node : nodes){
System.out.printf(format, node.getId(), node.getPid(), node.getName(), node.getUpNum(), node.getUpLevel()
, node.getDowNum(), node.getDownLevel());
}
}
Node getNode(int id){
for(Node node : nodes){
if(node.getId() == id) return node;
}
return null;
}
public static void main(String[] args) {
//make graph
Graph graph = new Graph(new Node(1, 0, "a"));
graph.add(new Node(2, 1, "b"));
graph.add(new Node(3, 1, "c"));
graph.add(new Node(4, 2, "d"));
graph.add(new Node(5, 2, "e"));
graph.analyze();
graph.print();
}
}
class Node {
private final int id,pid;
private int upnum = 0, uplevel = 0, downum = 0, downlevel = 0;
private final String name;
Node(int id, int pid, String name) {
super();
this.id = id;
this.pid = pid;
this.name = name;
}
int getId() { return id; }
int getPid() { return pid; }
String getName() { return name; }
int getUpNum() { return upnum; }
void setUpNum(int upnum) { this.upnum = upnum; }
int getUpLevel() { return uplevel; }
void setUpLevel(int uplevel) { this.uplevel = uplevel; }
int getDowNum() { return downum; }
void setDowNum(int downum) { this.downum = downum; }
int getDownLevel() { return downlevel; }
void setDownLevel(int downlevel) { this.downlevel = downlevel; }
}输出:

https://stackoverflow.com/questions/55094622
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