我得到了一个varchar字段,比如值为174,但是当我cast(field as decimal(3,1))时,它总是给我99.9?我怎样才能把它转换成17.4?或者我必须在源级更改输入,以十进制本身作为输入?
发布于 2016-06-07 17:47:25
这是因为174不能用小数点之前的2位和小数点之后的1位来表示。decimal(3,1)的意思是“总计3位,小数点之后的1位。
mysql> select cast('174' as decimal(3,1));
+-----------------------------+
| cast('174' as decimal(3,1)) |
+-----------------------------+
| 99.9 |
+-----------------------------+
1 row in set, 1 warning (0.00 sec)它给出了一个警告,可以用以下方式显示:
mysql> show warnings;
+---------+------+----------------------------------------------------------------------+
| Level | Code | Message |
+---------+------+----------------------------------------------------------------------+
| Warning | 1264 | Out of range value for column 'cast('174' as decimal(3,1))' at row 1 |
+---------+------+----------------------------------------------------------------------+
1 row in set (0.00 sec)将该数字除以10,然后重试:
mysql> select cast('174'/10 as decimal(3,1));
+--------------------------------+
| cast('174'/10 as decimal(3,1)) |
+--------------------------------+
| 17.4 |
+--------------------------------+
1 row in set (0.00 sec)https://stackoverflow.com/questions/37685929
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