我有一个HashSet<String>,里面充满了名为shingles的字符串(如果将字符串"Fizzbuzz“分解成带状,就会得到"Fi”、"iz“、"zz”、"zb“、"bu”、"uz“、"zz”。)不重要,但这就是板子在这种情况下的含义)。
我试图通过以下方法返回HashSet内容的字符串:
public String getShinglesAsString() {
String shingles = "";
for (String shingle : this.shingles) {
shingles += shingle + " ";
}
return shingles;
}for (String shingle : this.shingles)正在抛出一个ClassCastException。具体的消息是Exception in thread "main" java.lang.ClassCastException: java.lang.Integer cannot be cast to java.lang.CharSequence。
我也尝试过使用Iterator对象,我也遇到了同样的问题。这是我的代码,用于从输入给构造函数的字符串中生成带状代码:
// Will generate a new set of shingles based on sentence
public void generateShingles() {
shingles = new HashSet<>();
for (int i=0; i<getSentence().length()-1; i++) {
getShingles().add(getSentence().charAt(i) + getSentence().charAt(i+1));
}
}编辑:这是minmal, complete, verifiable example:
public class SentenceWithShingles {
private String sentence;
private Set<String> shingles;
// Constructor
public SentenceWithShingles(String sentence) {
this.sentence = sentence;
generateShingles();
}
// Will generate a new set of shingles based on sentence
public void generateShingles() {
shingles = new HashSet<>();
for (int i=0; i<getSentence().length()-1; i++) {
getShingles().add(getSentence().charAt(i) + getSentence().charAt(i+1));
}
}
public void setSentence(String sentence) {
this.sentence = sentence;
}
public Set getShingles() {
return shingles;
}
public String getShinglesAsString() {
String shingles = "";
for (String shingle : this.shingles) {
shingles += shingle + " ";
}
return shingles;
}}
发布于 2015-02-17 00:32:18
错误在这里:
getShingles().add(getSentence().charAt(i) + getSentence().charAt(i+1));这一行将这两个字符相加在一起。而不是连接他们。
getShingles().add(getSentence().charAt(i) + "" + getSentence().charAt(i+1));将强制正确的语义学。
https://stackoverflow.com/questions/28552265
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