我使用这个查询在数据库中找到一个字符串,但是我得到了一个特定DB的错误:
在“似乎”附近不正确的语法。
所以我想知道原因
CREATE TABLE #Results (ColumnName nvarchar(370), ColumnValue nvarchar(3630))
SET NOCOUNT ON
DECLARE @TableName nvarchar(256), @ColumnName nvarchar(128), @SearchStr2 nvarchar(110)
SET @TableName = ''
SET @SearchStr2 = quotename( '%NQF%0028a%' , '''' )
WHILE @TableName IS NOT NULL
BEGIN
SET @ColumnName = ''
SET @TableName =
(
SELECT min(quotename(TABLE_SCHEMA) + '.' + quotename(TABLE_NAME))
FROM INFORMATION_SCHEMA.TABLES
WHERE TABLE_TYPE = 'BASE TABLE'
AND quotename(TABLE_SCHEMA) + '.' + quotename(TABLE_NAME) > @TableName
AND objectproperty(object_id(quotename(TABLE_SCHEMA) + '.' + quotename(TABLE_NAME)), 'IsMSShipped') = 0
)
WHILE (@TableName IS NOT NULL) AND (@ColumnName IS NOT NULL)
BEGIN
SET @ColumnName = (SELECT min(quotename(COLUMN_NAME))
FROM INFORMATION_SCHEMA.COLUMNS
WHERE TABLE_SCHEMA = parsename(@TableName, 2)
AND TABLE_NAME = parsename(@TableName, 1)
AND DATA_TYPE IN ('char', 'varchar', 'nchar', 'nvarchar')
AND quotename(COLUMN_NAME ) > @ColumnName )
IF @ColumnName IS NOT NULL
BEGIN
INSERT INTO #Results
EXEC
('SELECT ''' + @TableName + '.' + @ColumnName + ''', LEFT(' + @ColumnName + ', 3630)
FROM ' + @TableName + ' (NOLOCK) ' +
' WHERE ' + @ColumnName + ' LIKE ' + @SearchStr2
)
END
END
END
SELECT ColumnName , ColumnValue FROM #Results**strong text**
发布于 2013-10-29 06:49:18
看上去你的表名里有个空格。检查表的“似乎”作为其名称的一部分,并删除空格,如果可能的话。如果表名的更改不是选项,则将@TableName
变量包装在[]
中
https://stackoverflow.com/questions/19651250
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