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社区首页 >问答首页 >-215:函数‘>=’中的断言失败的npoint == 0 && (depth == CV_32F \x\\深度== CV_32S)

-215:函数‘>=’中的断言失败的npoint == 0 && (depth == CV_32F \x\\深度== CV_32S)
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Stack Overflow用户
提问于 2020-03-04 04:04:15
回答 1查看 1.1K关注 0票数 0

我尝试这段代码从系统,并已经解决了大多数问题的wrt版本错配。但无法修复此错误:-

代码语言:javascript
复制
 line 61, in segment_characters_from_plate
    c = max(cnts, key=cv2.contourArea)
cv2.error: OpenCV(4.2.0) /io/opencv/modules/imgproc/src/shapedescr.cpp:315: error: (-215:Assertion failed) npoints >= 0 && (depth == CV_32F || depth == CV_32S) in function 'contourArea'

我迄今尝试过的(但都没有成功):-

OpenCV(4.0.0)断言函数“contourArea”失败

Python中的OpenCV轮廓:如何解决“超出范围的列表索引”

contourArea函数中的32S)

代码如下 :--

代码语言:javascript
复制
import cv2
import numpy as np

import imutils
from skimage.filters import threshold_local
from skimage import measure


def sort_contours_left_to_right(character_contours):
    """
    Sort contours from left to right
    """
    i = 0
    boundingBoxes = [cv2.boundingRect(c) for c in character_contours]
    (character_contours, boundingBoxes) = zip(*sorted(zip(character_contours, boundingBoxes),
                                                key=lambda b:b[1][i], reverse=False))
    return character_contours


def segment_characters_from_plate(plate_img, fixed_width):
    """
    extract the Value component from the HSV color space and apply adaptive thresholding
    to reveal the characters on the license plate
    """
    V = cv2.split(cv2.cvtColor(plate_img, cv2.COLOR_BGR2HSV))[2]
    T = threshold_local(V, 29, offset=15, method='gaussian')
    thresh = (V > T).astype('uint8') * 255
    thresh = cv2.bitwise_not(thresh)

    # resize the license plate region to a canoncial size
    plate_img = imutils.resize(plate_img, width=fixed_width)
    thresh = imutils.resize(thresh, width=fixed_width)
    bgr_thresh = cv2.cvtColor(thresh, cv2.COLOR_GRAY2BGR)
    bgr_thresh = np.uint8(bgr_thresh)
    # perform a connected components analysis and initialize the mask to store the locations
    # of the character candidates
    labels = measure.label(thresh, neighbors=8, background=0)
    charCandidates = np.zeros(thresh.shape, dtype='uint8')

    # loof over the unique components
    characters = []
    for label in np.unique(labels):
        # if this is the background label, ignore it
        if label == 0:
            continue
        # otherwise, construct the label mask to display only connected components for the
        # current label, then find contours in the label mask
        labelMask = np.zeros(thresh.shape, dtype='uint8')
        labelMask[labels == label] = 255
        cnts = cv2.findContours(labelMask, cv2.RETR_EXTERNAL, cv2.CHAIN_APPROX_SIMPLE)
        cnts = cnts[0] if imutils.is_cv2() else cnts[1]

        # ensure at least one contour was found in the mask
        if len(cnts) > 0:

            # grab the largest contour which corresponds to the component in the mask, then
            # grab the bounding box for the contour
            c = max(cnts, key=cv2.contourArea)
            (boxX, boxY, boxW, boxH) = cv2.boundingRect(c)

            # compute the aspect ratio, solodity, and height ration for the component
            aspectRatio = boxW / float(boxH)
            solidity = cv2.contourArea(c) / float(boxW * boxH)
            heightRatio = boxH / float(plate_img.shape[0])

            # determine if the aspect ratio, solidity, and height of the contour pass
            # the rules tests
            keepAspectRatio = aspectRatio < 1.0
            keepSolidity = solidity > 0.15
            keepHeight = heightRatio > 0.5 and heightRatio < 0.95

            # check to see if the component passes all the tests
            if keepAspectRatio and keepSolidity and keepHeight and boxW > 14:
                # compute the convex hull of the contour and draw it on the character
                # candidates mask
                hull = cv2.convexHull(c)
                cv2.drawContours(charCandidates, [hull], -1, 255, -1)

    _, contours, hier = cv2.findContours(charCandidates, cv2.RETR_EXTERNAL, cv2.CHAIN_APPROX_SIMPLE)
    if contours:
        contours = sort_contours_left_to_right(contours)
        characters = []

        addPixel = 4 # value to be added to each dimension of the character
        for c in contours:
            (x,y,w,h) = cv2.boundingRect(c)
            if y > addPixel:
                y = y - addPixel
            else:
                y = 0
            if x > addPixel:
                x = x - addPixel
            else:
                x = 0
            temp = bgr_thresh[y:y+h+(addPixel*2), x:x+w+(addPixel*2)]
            characters.append(temp)
        return characters
    else:
        return None
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回答 1

Stack Overflow用户

发布于 2020-03-04 05:45:35

cv2.findContours的方法签名随每个主要版本的变化而变化。它是

代码语言:javascript
复制
contours, hierarchy = cv2.findContours(...)

OpenCV 2.x.xOpenCV 4.x.x都是,但是

代码语言:javascript
复制
image, contours, hierarchy = cv2.findContours(...)

为了OpenCV 3.x.x

现在,(第一个)问题是以下代码:

代码语言:javascript
复制
cnts = cnts[0] if imutils.is_cv2() else cnts[1]

您只检查使用的版本是否为OpenCV 2.x.x,因此cnts[1]也用于OpenCV 4.x.x,其中也应该是cnts[0]。最好将imutils版本检查替换为如下所示:

代码语言:javascript
复制
cnts = cnts[0] if len(cnts) == 2 else cnts[1]

在进一步更改方法签名之前,这将适用于所有主要版本的OpenCV。

请注意,这里还会出现另一个错误:

代码语言:javascript
复制
_, contours, hier = cv2.findContours(...)

这是特定于OpenCV 3.x.x的,所以最好也相应地修改该行。

希望这能帮上忙!

票数 1
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/60518911

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