加密(base64)密码未存储在数据库hsql中
加密(base64)密码未存储在数据库hsql中
提问于 2020-06-09 09:10:40
我试图从Java的输入中简单地将一个base64加密密码存储在数据库中。
为此，我使用hsqldb，我的密码列类型是varbinary(255)。但是，当我试图将它存储在数据库中时，我只会得到下面的错误。我甚至试图将密码列的类型更改为BLOB或varchar，但它仍然给出了相同的错误。请帮帮忙。
错误：
com.loginjava.exception.LoginException: Not possible to update the password
at com.loginjava.classes.PasswordHandler.UpdatePassword(PasswordHandler.java:36)
at com.loginjava.servlets.ForgotPasswordReset.doPost(ForgotPasswordReset.java:55)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:660)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:741)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:231)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:166)
at org.apache.tomcat.websocket.server.WsFilter.doFilter(WsFilter.java:53)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:193)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:166)
at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:202)
at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:96)
at org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:541)
at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:139)
at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:92)
at org.apache.catalina.valves.AbstractAccessLogValve.invoke(AbstractAccessLogValve.java:690)
at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:74)
at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:343)
at org.apache.coyote.http11.Http11Processor.service(Http11Processor.java:373)
at org.apache.coyote.AbstractProcessorLight.process(AbstractProcessorLight.java:65)
at org.apache.coyote.AbstractProtocol$ConnectionHandler.process(AbstractProtocol.java:868)
at org.apache.tomcat.util.net.NioEndpoint$SocketProcessor.doRun(NioEndpoint.java:1590)
at org.apache.tomcat.util.net.SocketProcessorBase.run(SocketProcessorBase.java:49)
at java.base/java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1128)
at java.base/java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:628)
at org.apache.tomcat.util.threads.TaskThread$WrappingRunnable.run(TaskThread.java:61)
at java.base/java.lang.Thread.run(Thread.java:830)
Caused by: java.sql.SQLDataException: data exception: invalid character value for cast
at org.hsqldb.jdbc.JDBCUtil.sqlException(Unknown Source)
at org.hsqldb.jdbc.JDBCUtil.sqlException(Unknown Source)
at org.hsqldb.jdbc.JDBCPreparedStatement.setParameter(Unknown Source)
at org.hsqldb.jdbc.JDBCPreparedStatement.setString(Unknown Source)
at org.apache.tomcat.dbcp.dbcp2.DelegatingPreparedStatement.setString(DelegatingPreparedStatement.java:616)
at org.apache.tomcat.dbcp.dbcp2.DelegatingPreparedStatement.setString(DelegatingPreparedStatement.java:616)
at com.loginjava.classes.PasswordHandler.UpdatePassword(PasswordHandler.java:26)
... 25 more
Caused by: org.hsqldb.HsqlException: data exception: invalid character value for cast
at org.hsqldb.error.Error.error(Unknown Source)
at org.hsqldb.error.Error.error(Unknown Source)
at org.hsqldb.Scanner.convertToBinary(Unknown Source)
at org.hsqldb.types.BinaryType.castOrConvertToType(Unknown Source)
at org.hsqldb.types.BinaryType.convertToDefaultType(Unknown Source)
... 30 more 这里是我的Servlet:
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
String password = request.getParameter("password");
String token = request.getParameter("token");
if(PasswordHandler.CheckRequirements(password)) {
String encryptedpwd = Base64.getEncoder().encodeToString(password.getBytes());
try {
PasswordHandler.UpdatePassword(encryptedpwd, token);
} catch (SQLException e) {
e.printStackTrace();
}
String message = Constants.PWD_SUCCESS;
request.setAttribute("message", message);
request.getRequestDispatcher("reset-password.jsp?token=" + token).forward(request, response);
} else {
String message = Constants.PWD_FAIL;
request.setAttribute("message", message);
request.getRequestDispatcher("reset-password.jsp?token=" + token).forward(request, response);
}
} 这是PasswordHandler.java类：
public static void UpdatePassword(String encryptedpwd, String token) throws SQLException {
try
{
PreparedStatement ps = con.prepareStatement(
"UPDATE user SET password = ? WHERE token = ?");
ps.setString(1,encryptedpwd);
ps.setString(2,token);
ps.executeUpdate();
ps.close();
}
catch (Exception e) {
throw new LoginException("Not possible to update the password", e);
}
}回答 2
Stack Overflow用户
回答已采纳
发布于 2020-06-09 13:02:52
您已经将密码列定义为var二进制(255)。插入到此类列中的任何字符串都必须采用十六进制格式，例如，cd349956e2。您可以使用编码器将密码转换为二进制数组，然后在插入之前将二进制转换为十六进制。
也可以将列定义为varchar(255)，以将密码插入为base64字符串。
在任何情况下，密码通常不是直接存储在数据库中，而是作为一个安全散列存储。例如，SHA-256散列。
Stack Overflow用户
发布于 2020-06-09 09:17:45
在这里添加一个可能的解决方案，因为我的级别不允许我发表评论。
在队伍中：
PasswordHandler.UpdatePassword(encryptedpwd, token);验证变量加密and 的值和长度，检查数据库是否接受类型值(可能为null)和变量长度(可能大于DB中允许的长度)。
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原文链接：
https://stackoverflow.com/questions/62288152
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