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问如果元素相同但元素值不同，则使用jaxb解组xml
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Stack Overflow用户

提问于 2016-06-02 23:07:56

回答 1查看 827关注 0票数 0

您好，帮助请在xml文件中有一些相同的元素，这些元素在"name“属性的内容上有所不同。这些元素有不同的项集，如何进行解组？Xml：

        <?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\"?>
        <service-broker>
            <adapters>
                <adapter name=\"cdb\">
                        <protocol>JDBC</protocol>
                        <datasource>CdbAdapterDS</datasource>
                </adapter>

                <adapter name=\"fmss-sc\">
                    <protocol>BBBC</protocol>
                    <fleet-uc18-reason-codes>
                            <code>2</code>
                            <code>3</code>
                    </fleet-uc18-reason-codes>
                </adapter>
            </adapters>  
        </service-broker>

我需要在Cdb中执行对象2的解组，并对我的尝试进行FmssSc : General element - ServiceBroker.class

package jax;

import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlRootElement;

@XmlRootElement(name = "service-broker")
@XmlAccessorType(XmlAccessType.FIELD)
public class ServiceBroker {

    @XmlElement(name = "adapters")
    private Adapters adapters;

    public Adapters getAdapters() {
        return adapters;
    }

    public void setAdapters(Adapters adapters) {
        this.adapters = adapters;
    }
}

Adapters.class

package jax;

import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlElementWrapper;

@XmlAccessorType(XmlAccessType.FIELD)
class Adapters {

    @XmlElement
    private Cdb cdb;

    @XmlElement
    private FmssSc fmssSc;

    public Cdb getCdb() {
        return cdb;
    }

    public void setCdb(Cdb cdb) {
        this.cdb = cdb;
    }

    public FmssSc getFmssSc() {
        return fmssSc;
    }

    public void setFmssSc(FmssSc fmssSc) {
        this.fmssSc = fmssSc;
    }
}

Cdb.class

package jax;

import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlElement;

@XmlAccessorType(XmlAccessType.FIELD)
class Cdb {

    @XmlElement(name = "protocol")
    private String protocol;

    @XmlElement(name = "datasource")
    private String datasource;

    public String getProtocol() {
        return protocol;
    }

    public void setProtocol(String protocol) {
        this.protocol = protocol;
    }

    public String getDatasource() {
        return datasource;
    }

    public void setDatasource(String datasource) {
        this.datasource = datasource;
    }
}

FmssSc.class

package jax;

import java.util.ArrayList;
import java.util.List;
import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlElementWrapper;

@XmlAccessorType(XmlAccessType.FIELD)
class FmssSc {

    @XmlElement(name = "protocol")
    private String protocol;

    @XmlElementWrapper(name = "fleet-uc18-reason-codes")
    @XmlElement(name = "code")
    private List<String> code = new ArrayList<>();

    public String getProtocol() {
        return protocol;
    }

    public void setProtocol(String protocol) {
        this.protocol = protocol;
    }

    public List<String> getCode() {
        return code;
    }

    public void setCode(List<String> code) {
        this.code = code;
    }
}

演示：

package jax;

import java.io.StringReader;
import javax.xml.bind.JAXBContext;
import javax.xml.bind.JAXBException;
import javax.xml.bind.Unmarshaller;

public class Jax {

    public static final String adapter =
            "<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\"?>\n" +
            "<service-broker>" + 
                "<adapters>" +
                    "<adapter name=\"cdb\">" +
                            "<protocol>JDBC</protocol>" +
                            "<datasource>CdbAdapterDS</datasource>" +
                    "</adapter>" +

                    "<adapter name=\"fmss-sc\">" +
                        "<protocol>BBBC</protocol>" +
                        "<fleet-uc18-reason-codes>" +
                                "<code>2</code>" +
                                "<code>3</code>" +
                        "</fleet-uc18-reason-codes>" +
                    "</adapter>" +
                "</adapters>"  +
            "</service-broker>";

    public static void main(String[] args) throws JAXBException {
        Jax jax = new Jax();
        jax.shouldUnmarshallAdapter();
    }

    public void shouldUnmarshallAdapter() throws JAXBException {
        StringReader reader = new StringReader(adapter);
        JAXBContext context = JAXBContext.newInstance(ServiceBroker.class);
        Unmarshaller u = context.createUnmarshaller();
        ServiceBroker sb = (ServiceBroker) u.unmarshal(reader);
        System.out.println(sb.getAdapters().getCdb().getProtocol());
    }
}

错误：

Exception in thread "main" java.lang.NullPointerException
    at jax.Jax.shouldUnmarshallAdapter(Jax.java:39)
    at jax.Jax.main(Jax.java:31)

xml

jaxb

unmarshalling

java

回答 1

Stack Overflow用户

发布于 2016-06-02 23:38:55

XML中的标记名"adapter“在Java类中没有等效项，即没有具有该名称的类" Adapters”的成员，因此实际上带有该标记的所有XML都将被忽略，因此Adapters实例中的变量cdb为null。NPE。并且: XML中的属性"name“决不会被Jaxb用来将所有子标记映射到cdb或fmssSc成员。您的Java代码将映射到该结构的XML：

<service-Broker>
   <adapters>
      <cdb>
        <protocol>
        <datasource>
      <fmssSc>
        <protocol>
        ....

票数 0

页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持

原文链接：

https://stackoverflow.com/questions/37595635

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