blocks|key|1894910|text|更新API+:由于我最初编写了此答案，因此对进行了增强，从而使此答案过时(或至少不完整)。有关详细信息，请参阅How+to+get+20%2B+result+from+Google+Places+API?。|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|1894911|原始答案|1894912|documentation表示Places+API最多可返回20个结果。这并不表示有任何方法可以更改该限制。因此，简短的答案似乎是:你不能。|1894913|当然，您可以通过对多个位置执行查询，然后合并/消除重复结果来实现某种程度上的伪造。不过，这是一种廉价的黑客攻击，可能不会很好地工作。我会先检查一下，以确保它没有违反服务条款。|1894914|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/9614258/how-to-get-20-result-from-google-places-api|1|http://code.google.com/apis/maps/documentation/places/#PlaceSearchResults^0|0|M|1J|19|0|0|0|4|0|0|D|1|0|0^^$0|@$1|2|3|4|5|6|7|V|8|@$9|W|A|X|B|C]]|D|@$9|Y|A|Z|1|10]]|E|$]]|$1|F|3|G|5|6|7|11|8|@$9|12|A|13|B|C]]|D|@]|E|$]]|$1|H|3|I|5|6|7|14|8|@]|D|@$9|15|A|16|1|17]]|E|$]]|$1|J|3|K|5|6|7|18|8|@]|D|@]|E|$]]|$1|L|3|-4|5|6|7|19|8|@]|D|@]|E|$]]]|M|$N|$5|O|P|Q|E|$R|S]]|T|$5|O|P|Q|E|$R|U]]]]

UPDATE: Since I originally wrote this answer, the API was enhanced, making this answer out of date (or, at least, incomplete). See <a href="https://stackoverflow.com/questions/9614258/how-to-get-20-result-from-google-places-api">How to get 20+ result from Google Places API?</a> for more information.

ORIGINAL ANSWER:

The <a href="http://code.google.com/apis/maps/documentation/places/#PlaceSearchResults" rel="noreferrer">documentation</a> says that the Places API returns up to 20 results. It does not indicate that there is any way to change that limit. So, the short answer seems to be: You can't.

Of course, you might be able to sort of fake it by doing queries for several locations, and then merging/de-duplicating the results. It's kind of a cheap hack, though, and might not work very well. And I'd check first to make sure it doesn't violate the terms of service.

blocks|key|3509876|text|现在有可能超过20个结果(但最多60个)，接口中增加了一个参数page_token。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|3509877|3509878|从先前运行的搜索返回接下来的20个结果。设置page_token参数将使用以前使用的相同参数执行搜索-+page_token以外的所有参数都将被忽略。|blockquote|3509879|3509880|3509881|此外，您还可以参考accessing+additional+results部分，以查看有关如何进行分页的示例。|3509882|entityMap|0|LINK|mutability|MUTABLE|url|https://developers.google.com/places/documentation/#PlaceSearchRequests|1|https://developers.google.com/maps/documentation/javascript/places#PlaceSearchPaging^0|V|A|0|0|0|0|0|0|9|S|1|0^^$0|@$1|2|3|4|5|6|7|V|8|@]|9|@$A|W|B|X|1|Y]]|C|$]]|$1|D|3|-4|5|6|7|Z|8|@]|9|@]|C|$]]|$1|E|3|F|5|G|7|10|8|@]|9|@]|C|$]]|$1|H|3|-4|5|6|7|11|8|@]|9|@]|C|$]]|$1|I|3|-4|5|6|7|12|8|@]|9|@]|C|$]]|$1|J|3|K|5|6|7|13|8|@]|9|@$A|14|B|15|1|16]]|C|$]]|$1|L|3|-4|5|6|7|17|8|@]|9|@]|C|$]]]|M|$N|$5|O|P|Q|C|$R|S]]|T|$5|O|P|Q|C|$R|U]]]]

Now it is possible to have more than 20 results (but up to 60), a parameter <a href="https://developers.google.com/places/documentation/#PlaceSearchRequests">page_token</a> was added to the API.

<blockquote>
 Returns the next 20 results from a previously run search. Setting a page_token parameter will execute a search with the same parameters used previously — all parameters other than page_token will be ignored.
</blockquote>

Also you can refer to the <a href="https://developers.google.com/maps/documentation/javascript/places#PlaceSearchPaging">accessing additional results</a> section to see an example on how to do the pagination.

blocks|key|179818|text|作为对Eduardo的回应，谷歌现在确实添加了这一点，但Places文档也指出：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|179819|179820|最多可返回60个结果。|blockquote|179821|179822|179823|所以它还是有个帽子的。同样供参考的是，正如谷歌所说，"next_page_token“何时生效是有延迟的：|179824|179825|在发出next_page_token和生效之间有一段很短的延迟。|179826|179827|179828|下面是官方的Places+API文档：|179829|https://developers.google.com/places/documentation/|offset|length|179830|entityMap|0|LINK|mutability|MUTABLE|url^0|0|0|0|0|0|0|0|0|0|0|0|0|1F|0|0^^$0|@$1|2|3|4|5|6|7|11|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|12|8|@]|9|@]|A|$]]|$1|C|3|D|5|E|7|13|8|@]|9|@]|A|$]]|$1|F|3|-4|5|6|7|14|8|@]|9|@]|A|$]]|$1|G|3|-4|5|6|7|15|8|@]|9|@]|A|$]]|$1|H|3|I|5|6|7|16|8|@]|9|@]|A|$]]|$1|J|3|-4|5|6|7|17|8|@]|9|@]|A|$]]|$1|K|3|L|5|E|7|18|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|19|8|@]|9|@]|A|$]]|$1|N|3|-4|5|6|7|1A|8|@]|9|@]|A|$]]|$1|O|3|P|5|6|7|1B|8|@]|9|@]|A|$]]|$1|Q|3|R|5|6|7|1C|8|@]|9|@$S|1D|T|1E|1|1F]]|A|$]]|$1|U|3|-4|5|6|7|1G|8|@]|9|@]|A|$]]]|V|$W|$5|X|Y|Z|A|$10|R]]]]

In response to Eduardo, Google did add that now, but the Places documentation also states:

<blockquote>
 The maximum number of results that can be returned is 60. 
</blockquote>

so it still has a cap. also FYI, there is a delay for when the "next_page_token" will become valid, as Google states:

<blockquote>
 There is a short delay between when a next_page_token is issued, and when it will become valid.
</blockquote>

and here is the official Places API docs:

<a href="https://developers.google.com/places/documentation/" rel="noreferrer">https://developers.google.com/places/documentation/</a>

blocks|key|3510000|text|下面是查找其他结果的代码示例|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3510001|using+System;
using+System.Collections.Generic;
using+System.Net.Http;
using+System.Web.Script.Serialization;


namespace+ConsoleApplication1
{
++++class+Program
++++{
++++++++static+void+Main(string[]+args)
++++++++{
++++++++++++var+url+=+$"https://maps.googleapis.com/maps/api/place/nearbysearch/json?location={args[0]}&radius={args[1]}&type=restaurant&keyword={args[2]}&key={args[3]}";

++++++++++++dynamic+res+=+null;
++++++++++++var+places+=+new+List<PlacesAPIRestaurants>();
++++++++++++using+(var+client+=+new+HttpClient())
++++++++++++{
++++++++++++++++while+(res+==+null+%7C%7C+HasProperty(res,+"next_page_token"))
++++++++++++++++{
++++++++++++++++++++if+(res+!=+null+&&+HasProperty(res,+"next_page_token"))
++++++++++++++++++++{
++++++++++++++++++++++++if+(url.Contains("pagetoken"))
++++++++++++++++++++++++++++url+=+url.Split(new+string[]+{+"&pagetoken="+},+StringSplitOptions.None)[0];
++++++++++++++++++++++++url+%2B=+"&pagetoken="+%2B+res["next_page_token"];

++++++++++++++++++++}
++++++++++++++++++++var+response+=+client.GetStringAsync(url).Result;
++++++++++++++++++++JavaScriptSerializer+json+=+new+JavaScriptSerializer();
++++++++++++++++++++res+=+json.Deserialize<dynamic>(response);
++++++++++++++++++++if+(res["status"]+==+"OK")
++++++++++++++++++++{
++++++++++++++++++++++++foreach+(var+place+in+res["results"])
++++++++++++++++++++++++{
++++++++++++++++++++++++++++var+name+=+place["name"];
++++++++++++++++++++++++++++var+rating+=+HasProperty(place,"rating")+?+place["rating"]+:+null;
++++++++++++++++++++++++++++var+address+=+place["vicinity"];
++++++++++++++++++++++++++++places.Add(new+PlacesAPIRestaurants
++++++++++++++++++++++++++++{
++++++++++++++++++++++++++++++++Address+=+address,
++++++++++++++++++++++++++++++++Name+=+name,
++++++++++++++++++++++++++++++++Rating+=+rating
++++++++++++++++++++++++++++});
++++++++++++++++++++++++}
++++++++++++++++++++}
++++++++++++++++++++else+if+(res["status"]+==+"OVER_QUERY_LIMIT")
++++++++++++++++++++{
++++++++++++++++++++++++return;
++++++++++++++++++++}
++++++++++++++++}
++++++++++++}
++++++++}

++++++++public+static+bool+HasProperty(dynamic+obj,+string+name)
++++++++{
++++++++++++try
++++++++++++{
++++++++++++++++var+value+=+obj[name];
++++++++++++++++return+true;
++++++++++++}
++++++++++++catch+(KeyNotFoundException)
++++++++++++{
++++++++++++++++return+false;
++++++++++++}
++++++++}
++++}
}|code-block|syntax|javascript|3510002|希望这能节省你的时间。|3510003|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Here's code sample that will look for additional results

<pre><code>using System;
using System.Collections.Generic;
using System.Net.Http;
using System.Web.Script.Serialization;


namespace ConsoleApplication1
{
 class Program
 {
 static void Main(string[] args)
 {
 var url = $"https://maps.googleapis.com/maps/api/place/nearbysearch/json?location={args[0]}&amp;radius={args[1]}&amp;type=restaurant&amp;keyword={args[2]}&amp;key={args[3]}";

 dynamic res = null;
 var places = new List&lt;PlacesAPIRestaurants&gt;();
 using (var client = new HttpClient())
 {
 while (res == null || HasProperty(res, "next_page_token"))
 {
 if (res != null &amp;&amp; HasProperty(res, "next_page_token"))
 {
 if (url.Contains("pagetoken"))
 url = url.Split(new string[] { "&amp;pagetoken=" }, StringSplitOptions.None)[0];
 url += "&amp;pagetoken=" + res["next_page_token"];

 }
 var response = client.GetStringAsync(url).Result;
 JavaScriptSerializer json = new JavaScriptSerializer();
 res = json.Deserialize&lt;dynamic&gt;(response);
 if (res["status"] == "OK")
 {
 foreach (var place in res["results"])
 {
 var name = place["name"];
 var rating = HasProperty(place,"rating") ? place["rating"] : null;
 var address = place["vicinity"];
 places.Add(new PlacesAPIRestaurants
 {
 Address = address,
 Name = name,
 Rating = rating
 });
 }
 }
 else if (res["status"] == "OVER_QUERY_LIMIT")
 {
 return;
 }
 }
 }
 }

 public static bool HasProperty(dynamic obj, string name)
 {
 try
 {
 var value = obj[name];
 return true;
 }
 catch (KeyNotFoundException)
 {
 return false;
 }
 }
 }
}
</code></pre>

Hope this saves you some time.

blocks|key|3509760|text|我不确定你能得到更多。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3509761|3509762|+Places+API最多返回20个建立结果。|blockquote|3509763|3509764|3509765|http://code.google.com/apis/maps/documentation/places/#PlaceSearchResponses|offset|length|3509766|entityMap|0|LINK|mutability|MUTABLE|url^0|0|0|0|0|0|0|23|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|T|8|@]|9|@]|A|$]]|$1|C|3|D|5|E|7|U|8|@]|9|@]|A|$]]|$1|F|3|-4|5|6|7|V|8|@]|9|@]|A|$]]|$1|G|3|-4|5|6|7|W|8|@]|9|@]|A|$]]|$1|H|3|I|5|6|7|X|8|@]|9|@$J|Y|K|Z|1|10]]|A|$]]|$1|L|3|-4|5|6|7|11|8|@]|9|@]|A|$]]]|M|$N|$5|O|P|Q|A|$R|I]]]]

Not sure you can get more.

<blockquote>
 The Places API returns up to 20 establishment results.
</blockquote>

<a href="http://code.google.com/apis/maps/documentation/places/#PlaceSearchResponses" rel="nofollow">http://code.google.com/apis/maps/documentation/places/#PlaceSearchResponses</a>

blocks|key|3795001|text|如果问题是不是所有存在于搜索半径内的银行都可能被返回，我建议限制搜索半径，而不是发出多个自动查询。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3795002|将半径设置为不可能超过20+(60)个组的值。然后让用户很容易(在GUI方面)手动敲定更多的查询--类似于绘制查询。|3795003|在一个更大的地区返回数千家银行可能需要你依赖自己的银行数据库-如果你有系统地工作，这是可以实现的。|3795004|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|H|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|I|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|J|8|@]|9|@]|A|$]]|$1|F|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|G|$]]

If the problem is that not all banks that exists inside the search radius might not be returned, I would suggest limiting the search radius instead of issuing multiple automated queries. 

Set the radius to some value in which it is impossible to get more then 20 (60) banks. Then make it easy (GUI-wise) for the user to hammer out more queries manually - sort of painting a query.

Returning thousands of banks in a larger region will likely require you to rely on your own database of banks - which could be achievable if you work on it systematically.

blocks|key|3510030|text|你可以抓取Google+Places的搜索结果，然后按照分页来获取特定位置的200-300个位置(从10到15页的搜索结果)。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3510031|或者，您可以使用SerpApi访问从Google+Places提取的数据。它有免费试用版。|offset|length|3510032|Full+example|3510033|#+Package:+https://pypi.org/project/google-search-results

from+serpapi+import+GoogleSearch
import+os

params+=+{
++++"api_key":+os.getenv("API_KEY"),
++++"engine":+"google",
++++"q":+"restaurants",
++++"location":+"United+States",
++++"tbm":+"lcl",
++++"start":+0
}

search+=+GoogleSearch(params)
data+=+search.get_dict()

for+local_result+in+data['local_results']:
++++print(
++++++++f"Position:+{local_result['position']}\nTitle:+{local_result['title']}\n"
++++)

while+('next'+in+data['serpapi_pagination']):
++++search.params_dict["start"]+%2B=+len(data['local_results'])
++++data+=+search.get_dict()

++++print(f"Current+page:+{data['serpapi_pagination']['current']}\n")

++++for+local_result+in+data['local_results']:
++++++++print(
++++++++++++f"Position:+{local_result['position']}\nTitle:+{local_result['title']}\n"
++++++++)|code-block|syntax|javascript|3510034|输出|style|BOLD|3510035|Current+page:+11

Position:+1
Title:+Carbone

Position:+2
Title:+Elmer's+Restaurant+(Palm+Springs,+CA)

Position:+3
Title:+The+Table+Vegetarian+Restaurant

...|3510036|免责声明：我在SerpApi工作。|3510037|entityMap|0|LINK|mutability|MUTABLE|url|https://serpapi.com/places-results|1|https://repl.it/@serpapi/google-places-serpapi^0|0|8|7|0|0|0|C|1|0|0|0|2|0|0|0|4|0^^$0|@$1|2|3|4|5|6|7|14|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|15|8|@]|9|@$D|16|E|17|1|18]]|A|$]]|$1|F|3|G|5|6|7|19|8|@]|9|@$D|1A|E|1B|1|1C]]|A|$]]|$1|H|3|I|5|J|7|1D|8|@]|9|@]|A|$K|L]]|$1|M|3|N|5|6|7|1E|8|@$D|1F|E|1G|O|P]]|9|@]|A|$]]|$1|Q|3|R|5|J|7|1H|8|@]|9|@]|A|$K|L]]|$1|S|3|T|5|6|7|1I|8|@$D|1J|E|1K|O|P]]|9|@]|A|$]]|$1|U|3|-4|5|6|7|1L|8|@]|9|@]|A|$]]]|V|$W|$5|X|Y|Z|A|$10|11]]|12|$5|X|Y|Z|A|$10|13]]]]

You can scrape Google Places results and follow pagination to get 200-300 places for a specific location (from 10 to 15 pages of search results).
Alternatively, you can use <a href="https://serpapi.com/places-results" rel="nofollow noreferrer">SerpApi</a> to access extracted data from Google Places. It has a free trial.
<a href="https://repl.it/@serpapi/google-places-serpapi" rel="nofollow noreferrer">Full example</a>
<pre class="lang-py prettyprint-override"><code># Package: https://pypi.org/project/google-search-results

from serpapi import GoogleSearch
import os

params = {
 &quot;api_key&quot;: os.getenv(&quot;API_KEY&quot;),
 &quot;engine&quot;: &quot;google&quot;,
 &quot;q&quot;: &quot;restaurants&quot;,
 &quot;location&quot;: &quot;United States&quot;,
 &quot;tbm&quot;: &quot;lcl&quot;,
 &quot;start&quot;: 0
}

search = GoogleSearch(params)
data = search.get_dict()

for local_result in data['local_results']:
 print(
 f&quot;Position: {local_result['position']}\nTitle: {local_result['title']}\n&quot;
 )

while ('next' in data['serpapi_pagination']):
 search.params_dict[&quot;start&quot;] += len(data['local_results'])
 data = search.get_dict()

 print(f&quot;Current page: {data['serpapi_pagination']['current']}\n&quot;)

 for local_result in data['local_results']:
 print(
 f&quot;Position: {local_result['position']}\nTitle: {local_result['title']}\n&quot;
 )
</code></pre>
Output
<pre><code>Current page: 11

Position: 1
Title: Carbone

Position: 2
Title: Elmer's Restaurant (Palm Springs, CA)

Position: 3
Title: The Table Vegetarian Restaurant

...
</code></pre>
Disclaimer: I work at SerpApi.

I want to develop a map application which will display the banks near a given place.

I use the Places library to search and everytime it just return 20 results. What should I do if I want more results?

Obtaining more than 20 results with Google Places API

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我想开发一个地图应用程序，将显示附近的银行给定的地方。我使用Places库进行搜索，每次它只返回20个结果。如果我想要更多的结果，我应该怎么做？

问使用Google Places API获取20多个结果
EN

回答 7

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问使用Google Places API获取20多个结果EN

回答 7

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问使用Google Places API获取20多个结果
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