我有一个包含Name、longitude和latitude列的数据框。我想要一个函数,它遍历每一行,从栅格堆栈中提取值,并基于Name列编写csv文件。
Name Lon Lat
Name1 11.11 47.87
Name2 150.1 -40.4
Name3 -50.2 -3.5
Name4 -100.3 49.8
library(raster)
s <- stack(replicate(5, {raster(matrix(runif(2160*4320), 2160),
xmn=-180, xmx=180, ymn=-90, ymx=90)}))
I can do that one by one:
location <- data.frame(11.11, 47.87)
ex <- extract(s, location)
write.csv(ex, "Name1.csv")发布于 2016-01-12 02:01:50
一种非常传统的方法使用for循环。
d1 <-c("Name1", "Name2","Name3", "Name4")
d2 <- c(11.11,150.1,-50.2,-100.3)
d3 <-c(47.87, -40.4, -3.5, 49.8)
data.df <-data.frame(d1,d2,d3)
for(i in 1:nrow(data.df))
{
location <- data.frame(data.df[i,2],data.df[,3])
ex <- extract(s, location)
fn1<-paste0(data.df[i,1],".csv")
write.csv(ex, fn1)
}将生成四个文件,其中包含如下信息:
"","layer.1","layer.2","layer.3","layer.4","layer.5"
"1",0.471816286211833,0.115963410818949,0.399704266572371,0.464667820138857,0.820669727399945
"2",0.616754011251032,0.354018000885844,0.602565947687253,0.86519843316637,0.660861984360963
"3",0.0691961287520826,0.128835600335151,0.199198298621923,0.968016018159688,0.597145217470825我希望这就是你想要的结果。可能会有一些更高级、更高效的方法(基于apply-family?)作为一个R初学者,我也很感兴趣。
发布于 2016-01-13 05:28:18
使用apply:
library(raster)
s <- stack(replicate(5, {raster(matrix(runif(2160*4320), 2160),
xmn=-180, xmx=180, ymn=-90, ymx=90)}))
d1 <-c("Name1", "Name2","Name3", "Name4")
d2 <- c(11.11,150.1,-50.2,-100.3)
d3 <-c(47.87, -40.4, -3.5, 49.8)
data.df <- data.frame("Name" = d1, "Lon" = d2, "Lat" = d3)
apply(X = data.df, 1, function(x, s) {
location <- as.numeric(c(x[2], x[3]))
ex <- extract(s, location)
write.csv(ex, paste0(x[1], ".csv"))
}, s = s)请注意,如果要在函数中使用它,则必须将s对象作为附加参数传递给函数。
https://stackoverflow.com/questions/34727250
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